2x^2-5x+20=3x

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Solution for 2x^2-5x+20=3x equation: 



2x^2-5x+20=3x

We move all terms to the left:

2x^2-5x+20-(3x)=0

We add all the numbers together, and all the variables

2x^2-8x+20=0

a = 2; b = -8; c = +20;
Δ = b2-4ac
Δ = -82-4·2·20
Δ = -96
Delta is less than zero, so there is no solution for the equation

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